Skip to main content

Solving a system by substitution

Solve one equation for a variable and substitute it into the other.

The common mistake

Substituting back into the same equation you rearranged, which gives 0 = 0 and no answer.

Instead: Rearrange one equation, substitute into the other one, solve, then plug back in for the second variable.

Worked example with Guide me

Solve y = 2x and x + y = 9.

  1. Sugar · Replace y in the second equation.
    Student · x + 2x = 9.
  2. Sugar · Solve for x.
    Student · 3x = 9, so x = 3.
  3. Sugar · Now find y.
    Student · y = 2(3) = 6.

Answer: (3, 6)

Try 3 practice questions

  1. 1. Solve y = x + 1 and 2x + y = 10.

    Show answer

    (3, 4)

  2. 2. Solve x = 3y and x + y = 8.

    Show answer

    (6, 2)

  3. 3. Solve y = 4 − x and y = x + 2.

    Show answer

    (1, 3)

Quick answers

What is the most common mistake with solving a system by substitution?
Substituting back into the same equation you rearranged, which gives 0 = 0 and no answer.
How do I get solving a system by substitution right?
Rearrange one equation, substitute into the other one, solve, then plug back in for the second variable.
Can you show a worked example?
Solve y = 2x and x + y = 9. (3, 6)

Related concepts

Save this as a miss — practice it before your test

Sugar brings it back for review until it sticks. Free, no card.

Save this as a miss — practice it before your test