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Subtracting before dividing in two-step equations

Undo the added number first, then divide by the coefficient.

The common mistake

Dividing first and only dividing one term — turning 3x + 5 = 20 into x + 5 = 20/3.

Instead: Undo operations in reverse order: subtract or add the constant first, then divide both sides by the number on x.

Worked example with Guide me

Solve 3x + 5 = 20.

  1. Sugar · What's being done to x, and in what order?
    Student · It's multiplied by 3, then 5 is added.
  2. Sugar · So what do we undo first? Subtract 5 from both sides — what's on the right?
    Student · 15, so 3x = 15.
  3. Sugar · Now undo the multiply. What is x?
    Student · 15 ÷ 3 = 5.

Answer: x = 5. Check: 3(5) + 5 = 20.

Try 3 practice questions

  1. 1. Solve 4x + 7 = 31.

    Show answer

    x = 6

  2. 2. Solve 5x − 3 = 22.

    Show answer

    x = 5

  3. 3. Solve 2x + 9 = 1.

    Show answer

    x = −4

Quick answers

What is the most common mistake with subtracting before dividing in two-step equations?
Dividing first and only dividing one term — turning 3x + 5 = 20 into x + 5 = 20/3.
How do I get subtracting before dividing in two-step equations right?
Undo operations in reverse order: subtract or add the constant first, then divide both sides by the number on x.
Can you show a worked example?
Solve 3x + 5 = 20. x = 5. Check: 3(5) + 5 = 20.

Related concepts

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Save this as a miss — practice it before your test