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Solving quadratics with the zero-product rule

Set the equation to zero, factor, then set each factor to zero.

The common mistake

Factoring when the equation isn't equal to zero, e.g. x² + x = 6 solved as x(x + 1) = 6 → x = 6.

Instead: Move everything to one side first so it equals 0, then factor and solve each bracket.

Worked example with Guide me

Solve x² + x = 6.

  1. Sugar · Is one side zero?
    Student · No — subtract 6: x² + x − 6 = 0.
  2. Sugar · Factor it.
    Student · (x + 3)(x − 2) = 0.
  3. Sugar · When is each bracket zero?
    Student · x = −3 or x = 2.

Answer: x = −3 or x = 2

Try 3 practice questions

  1. 1. Solve x² − 5x + 6 = 0.

    Show answer

    x = 2 or x = 3

  2. 2. Solve x² = 4x.

    Show answer

    x = 0 or x = 4

  3. 3. Solve x² − 16 = 0.

    Show answer

    x = 4 or x = −4

Quick answers

What is the most common mistake with solving quadratics with the zero-product rule?
Factoring when the equation isn't equal to zero, e.g. x² + x = 6 solved as x(x + 1) = 6 → x = 6.
How do I get solving quadratics with the zero-product rule right?
Move everything to one side first so it equals 0, then factor and solve each bracket.
Can you show a worked example?
Solve x² + x = 6. x = −3 or x = 2

Related concepts

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